Maths encyclopedia and lessons  
Search

Mathematics Encyclopedia and Lessons

 
     
 

Lessons

Popular
Subjects

algebra
arithmetic
calculus
equations
geometry
differential equations
trigonometry
number theory
probability theory
more
 

References

applied mathematics
mathematical games
mathematicians
more
 
 

Prediction interval

In statistics, a prediction interval bears the same relationship to a future observation that a confidence interval bears to an unobservable population parameter.

Example

Suppose one has drawn a sample from a normally distributed population. The mean and standard deviation of the population are unknown except insofar as they can be estimated based on the sample. It is desired to predict the next observation. Let n be the sample size; let μ and σ be respectively the unobservable mean and standard deviation of the population. Let X1, ..., Xn, be the sample; let Xn+1 be the future observation to be predicted. Let

\overline{X}_n=(X_1+\cdots+X_n)/n

and

S_n^2={1 \over n-1}\sum_{i=1}^n (X_i-\overline{X}_n)^2.

Then it is fairly routine to show that

{X_{n+1}-\overline{X}_n \over \sqrt{S_n^2+S_n^2/n}} = {X_{n+1}-\overline{X}_n \over S_n\sqrt{1+1/n}}

has a Student's t-distribution with n − 1 degrees of freedom. Consequently we have

P\left(\overline{X}_n-A S_n\sqrt{1+(1/n)}\leq X_{n+1}   \leq\overline{X}_n+A S_n\sqrt{1+(1/n)}\,\right)=p

where A is the 100(1 − (p/2))th percentile of Student's t-distribution with n − 1 degrees of freedom. Therefore the numbers

\overline{X}_n\pm A S_n\sqrt{1+(1/n)}

are the endpoints of a 100p% prediction interval for Xn+1.

See also

Seymour Geisser

01-04-2007 01:18:14
The contents of this article are licensed from Wikipedia.org
under the GNU Free Documentation License. How to see transparent copy