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Inverse functions and differentiation

In mathematics, the inverse of a function y = f(x) is a function that, in some fashion, "undoes" the effect of f (see inverse function for a formal and detailed definition). The inverse of f is denoted f - 1. The statements y=f(x) and x=f-1(y) are equivalent.

Differentiation in calculus is the process of obtaining a derivative. The derivative of a function gives the slope at any point.

\frac{dy}{dx} denotes the derivative of the function y = f(x) with respect to x.

\frac{dx}{dy} denotes the derivative of the function x = f(y) with respect to y.

The two derivatives are, as the Leibniz notation suggests, reciprocal, that is

\frac{dx}{dy}\,\cdot\, \frac{dy}{dx} = 1

This is a direct consequence of the chain rule, since

\frac{dx}{dy}\,\cdot\, \frac{dy}{dx} = \frac{dx}{dx}

and the derivative of x with respect to x is 1. Geometrically, a function and inverse function have graphs that are reflections, in the line y=x. This reflection operation turns the gradient of any line into its reciprocal.

Examples

  • y = x2 (for positive x) has inverse x = \sqrt{y}.
\frac{dy}{dx} = 2x  \mbox{ }\mbox{ }\mbox{ }\mbox{ }; \mbox{ }\mbox{ }\mbox{ }\mbox{ } \frac{dx}{dy} = \frac{1}{2\sqrt{y}}
\frac{dy}{dx}\,\cdot\,\frac{dx}{dy}  =  2x . \frac{1}{2\sqrt{y}}  =  \frac{2x}{2x}  =  1

At x=0, however, there is a problem: the graph of the square root function becomes vertical, corresponding to a horizontal tangent for the square function.

  • y = ex has inverse x = ln(y) (for positive y).
\frac{dy}{dx} = e^x \mbox{ }\mbox{ }\mbox{ }\mbox{ }; \mbox{ }\mbox{ }\mbox{ }\mbox{ } \frac{dx}{dy} = \frac{1}{y}
\frac{dy}{dx}\,.\,\frac{dx}{dy}  =  e^x . \frac{1}{y}  =  \frac{e^x}{e^x}  =  1

Additional properties

  • Integrating this relationship gives
{f^{-1}}(y)=\int\frac{1}{f'(x)}\,\cdot\,{dx} + c
This is only useful if the integral exists. In particular we need f'(x) to be non-zero across the range of integration.
It follows that functions with continuous derivative have inverses in a neighbourhood of every point where the derivative is non-zero. This need not be true if the derivative is not continuous.

Related topics

calculus, inverse functions, chain rule, inverse function theorem, implicit function theorem.

01-04-2007 01:18:14
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